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  4. In the reaction sequence (CH)3-C≡ C-H overset(CH)3 MgBr arrow (CH)4+(.A.) arrow (ii) H2 O / H+(i) (CO)2(.B.) B will be

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Q. In the reaction sequence
$\left(CH\right)_{3}-C\equiv C-H\overset{\left(CH\right)_{3} MgBr}{ \rightarrow }\left(CH\right)_{4}+\left(\right.A\left.\right) \rightarrow _{\left(ii\right) \, H_{2} O / H^{+}}^{\left(i\right) \, \left(CO\right)_{2}}\left(\right.B\left.\right)$
B will be

NTA AbhyasNTA Abhyas 2022

Solution:

Here the compounds A and B are as follows
$\left(CH\right)_{3}-C\equiv C-H\underset{- \left(CH\right)_{4}}{\overset{\left(CH\right)_{3} MgBr}{ \rightarrow }}\underset{\left(\right. A \left.\right)}{\left(CH\right)_{3} - C \equiv C - MgBr} \rightarrow _{\left(ii\right) H_{2} O / H^{+}}^{\left(\right. i \left.\right) \left(CO\right)_{2}}\underset{\left(\right. B \left.\right)}{\left(CH\right)_{3} - C \equiv C - COOH}$