Question

In the reaction sequence $ C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[(ii){{H}_{2}}O/Zn]{(i){{O}_{3}}}\Pr oducts $ Products will be

• A. $ C{{H}_{3}}COC{{H}_{3}} $
• B. $ C{{H}_{3}}COC{{H}_{2}}OH $
• C. $ C{{H}_{3}}COOH+HCOOH $
• D. $ C{{H}_{3}}CHO+HCHO $

Answer 1

Answer: (D)

Key Idea: The reaction is ozonolysis. During the reaction $ C=C $ breaks to give carbonyl compounds. $ C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[{{H}_{2}}O/2]{{{O}_{3}}}\underset{acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\,+\underset{formaldehyde}{\mathop{HCHO}}\, $