1. Tardigrade
  2. Question
  3. Chemistry
  4. In the reaction: Na2S2O3 + 4Cl2 + 5H2O → Na2SO4 + H2SO4 + 8HCI, the equivalent weight of Na2S2O3 will be: (M = molecular weight of Na2S2O3)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In the reaction: $Na_2S_2O_3 + 4Cl_2 + 5H_2O \to Na_2SO_4 + H_2SO_4 + 8HCI,$ the equivalent weight of $Na_2S_2O_3$ will be: (M = molecular weight of $Na_2S_2O_3$)

Some Basic Concepts of Chemistry

Solution:

$Na_2^{+2}S_2O_3 \to Na_2^{+6}SO_4$
the total change in oxidation number $= 4 \times 2 = 8$
$\therefore E_{Na_2S_2O_3} = \frac{mol.wt.}{v f}=\frac{M}{8}$