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Chemistry
In the reaction. HCOOH+CH3COOH xrightarrow[Δ ]MnOX; Product X is
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Q. In the reaction. $ HCOOH+C{{H}_{3}}COOH\xrightarrow[\Delta ]{MnO}X; $ Product X is
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A
$ HCHO $
B
$ C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-H $
C
$ C{{H}_{3}}-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}} $
D
$ H-\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{C}}\,-O-{{C}_{2}}{{H}_{5}} $
Solution:
$ \underset{formic\text{ }acid}{\mathop{HCOOH}}\,+\underset{acetic\text{ }acid}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow[{}]{MnO,\Delta }\underset{acetaldehyde}{\mathop{C{{H}_{3}}CHO}}\, $ $ +{{H}_{2}}\text{O}+C{{O}_{2}} $