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  3. Chemistry
  4. In the reaction CrO5 + H2SO4 → Cr2(S)2 + H2O + O2 one mole of CrO5 will liberate how many moles of O2:

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Q. In the reaction $CrO_{5} + H_{2}SO_{4} \to Cr_{2}(S)_{2} + H_{2}O + O_{2}$ one mole of $CrO_{5}$ will liberate how many moles of $O_{2}$:

Redox Reactions

Solution:

$2CrO_{5} + 3H_{2}SO_{4} \to Cr_{2}(SO)_{3}+ 3H_{2}O+ 7/2O_{2}$ 1 mole $CrO_{5}$ liberates $ \to 7/2$ mole of $O_{2}$,