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  4. In the reaction, Cl2 + CH4 xrightarrowhv CH3Cl + HCl presence of a small amount of oxygen

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Q. In the reaction, $Cl_2 + CH_4 \xrightarrow{hv} CH_3Cl + HCl$ presence of a small amount of oxygen

Hydrocarbons

Solution:

Halogenation of alkanes follows free radical mechanism and presence of a small amount of oxygen can slow down the reaction for a period of time depending upon the amount of oxygen. Oxygen reacts with methyl free radical to form less reactive free radical and acts as an inhibitor.