Question

In the reaction $CH_{3}\overset{*}{C}ONH_{2}\underset{\Delta }{\overset{P_{2} O_{5}}{ \rightarrow }}CH_{3}\overset{*}{C}N$ the hybridisation state of the $\overset{*}{C}$ atom changes from:

• A. $sp^{2}-sp$
• B. $sp^{3}-sp$
• C. $sp^{3}-sp^{2}$
• D. $sp^{2}-sp^{3}$

Answer 1

Answer: (A)

Here hybridisation state of the $\overset{*}{C}$ atom changes from $sp^{2}-sp$