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Q. In the reaction $Ca(OH)_2 + H_3PO_4 \to Ca_3(PO_4)_2 + H_2O$, the equivalent mass of $H_2O$ is: ($M$ molecular mass)

Some Basic Concepts of Chemistry

Solution:

In acid-base neutralisation $1 \,H^+$ combines with $1 \,OH^-$ to produce $1\, H_2O$, therefore its equivalent mass = molecular mass