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Chemistry
In the reaction C(s) + CO2(g) leftharpoons 2CO(g), the equilibrium pressure is 12 atm. If 50 % of CO2 reacts, then Kp will be:
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Q. In the reaction $C(s) + CO_{2}(g) \rightleftharpoons 2CO(g),$ the equilibrium pressure is $12\, atm$. If $50\%$ of $CO_{2}$ reacts, then $K_p$ will be:
Equilibrium
A
$12$ atm
26%
B
$16$ atm
37%
C
$20$ atm
4%
D
$24$ atm
33%
Solution:
$C(s)+CO_{2}(g) \rightleftharpoons 2CO(g)$
$P -P/2 \,\,P =\frac{3P}{2}=12$
So, $K_{P} =\frac {P^{2}}{(P/2)} =2P=2 \times 8=16$ atm