Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In the reaction $C(s) + CO_{2}(g) \rightleftharpoons 2CO(g),$ the equilibrium pressure is $12\, atm$. If $50\%$ of $CO_{2}$ reacts, then $K_p$ will be:

Equilibrium

Solution:

$C(s)+CO_{2}(g) \rightleftharpoons 2CO(g)$
$P -P/2 \,\,P =\frac{3P}{2}=12$
So, $K_{P} =\frac {P^{2}}{(P/2)} =2P=2 \times 8=16$ atm