Question

In the reaction, $ 3A+2B\xrightarrow{{}}2C, $ the equilibrium constant $ {{K}_{c}} $ is given by

• A. $ \frac{[3A]\times [2B]}{[C]} $
• B. $ \frac{{{[A]}^{3}}\times [B]}{[C]} $
• C. $ \frac{{{[C]}^{2}}}{{{[A]}^{3}}\times {{[B]}^{2}}} $
• D. $ \frac{[C]}{[3A]\times [2B]} $

Answer 1

Answer: (C)

$3 A+2 B \rightarrow 2 C$
$K_{C}=\frac{\text { concentration of products }}{\text { conentration of reactants }}$
$=\frac{[C]^{2}}{[A]^{3} \times[B]^{2}}$