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Q. In the reaction, $3 I _{2}+6 NaOH \rightarrow NaIO _{3}+5 NaI +3 H _{2} O$ oxidising agent is

Redox Reactions

Solution:

$ \overset{0}{3 I _{2}}+6 NaOH \rightarrow Na\overset{+5}{IO _{3}}+5 \overset{-1}{NaI} +3 H _{2} O$

In the given reaction, $I _{2}$ is reduced thus acts as oxidising agent.