Question

In the reaction $2 PCl _{5} \rightleftharpoons PCl _{4}^{+}+ PCl _{6}^{-}$, the change in hybridisation is from

• A. $sp ^{3} d$ to $sp ^{3}$ and $sp ^{3} d ^{2}$
• B. $s p^{3} d$ to $s p^{2}$ and $s p^{3}$
• C. $sp ^{3} d$ to $sp ^{3} d ^{2}$ and $sp ^{3} d ^{3}$
• D. $sp ^{3} d ^{2}$ to $sp ^{3}$ and $sp ^{3} d$

Answer 1

Answer: (A)

$PCl _{5}$ is $sp^{3}$ d-hybridized with trigonal bipyramidal. In $PCl _{4}^{+}$phosphorous is $sp ^{3}$ hybridized. $PCl _{6}^{-}$is $sp ^{3} d ^{2}$ hybridized with octahedral shape.