1. Tardigrade
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  3. Chemistry
  4. In the reaction 2N2O5 → 4NO2 +O2 initial pressure is 500 atm and rate constant K is 3.38 × 10-5 sec-1. After 10 minutes the final pressure of N2O5 is

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Q. In the reaction $2N_2O_5 \to 4NO_2 +O_2$ initial pressure is $500$ atm and rate constant $K$ is $3.38 \times 10^{-5} sec^{-1.}$ After 10 minutes the final pressure of $N_2O_5$ is

Chemical Kinetics

Solution:

$P_{0}=500\, atm$
$K=\frac{2.303}{t} log\frac{P_{0}}{P_{1}}$
$3.38\times10^{-5}=\frac{2.303}{10\times60}log\frac{500}{P_{t}}$
or $0.00880=log\frac{500}{P_{t}}\Rightarrow \frac{500}{1.02}=490\, atm$