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  4. In the reaction, 2Br-+ X2 arrow Br2+2X-; X2 is

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Q. In the reaction, $2Br^{-}+ X_{2} \rightarrow Br_{2}+2X^{-}; X_{2}$ is

The p-Block Elements - Part2

Solution:

$2Br^{-}+ Cl_{2} \rightarrow Br_{2}+2Cl^{-}$
Hence $X_2$ is $Cl_2.$