1. Tardigrade
  2. Question
  3. Physics
  4. In the radioactive decay law N = N0e-λ t the dimensions of λ are

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In the radioactive decay law $ N = N_{0}e^{-\lambda\, t} $ the dimensions of $ \lambda $ are

Haryana PMTHaryana PMT 2011

Solution:

$N=N_{0} e^{-\lambda t}$
Exponents are always dimensionless.
So, dimensions of $\lambda t=\left[M^{0} L^{0} T^{0}\right][\lambda][T]$
$=\left[M^{0} L^{0} T^{0}\right] [\lambda] \frac{\left[M^{0} L^{0} T^{0}\right]}{[T]}$
$=\left[M^{0} L^{0} T^{-1}\right]$