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  4. In the question number 18, the potential at a point 20 cm from the mid-point of the line joining the two charges in a plane normal to the line and passing through the mid-point is

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Q. In the question number $18$, the potential at a point $20\, cm$ from the mid-point of the line joining the two charges in a plane normal to the line and passing through the mid-point is

Electrostatic Potential and Capacitance

Solution:

From the figure, potential at $P$,
image
$V=\frac{q_{1}}{4\pi\varepsilon_{0}\left(PA\right)}+\frac{q_{2}}{4\pi\varepsilon_{0}\left(PB\right)}$
$=\frac{1}{4\pi\varepsilon_{0}\left(PA\right)}\left(q_{1}+q_{2}\right)$
$\left(\because PA=PB=\sqrt{\left(0.2\right)^{2}+\left(0.2\right)^{2}}=0.28\,m\right)$
$=\frac{9\times10^{9}\left(1.8+2.8\right)\times10^{-6}}{0.28}$
$=1.4\times10^{5}\,V$