1. Tardigrade
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  3. Chemistry
  4. In the process, O 2+ arrow O 22++e-the electron lost is from

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Q. In the process, $O _{2}^{+} \rightarrow O _{2}^{2+}+e^{-}$the electron lost is from

ManipalManipal 2019

Solution:

Correct answer is (b) antibonding $\pi$-orbital