Question

In the process electroplating, m g of silver is deposited when 4 ampere of current flows for 2 minutes. The amount (in g) of silver deposited by 6 ampere of current flowing for 40 sec will be

• A. 4 m
• B. $\frac{m}{2}$
• C. $\frac{4 m}{3}$
• D. 3 m

Answer 1

Answer: (B)

$\frac{W_{1}}{W_{2}}=\frac{Q_{1}}{Q_{2}}=\frac{I_{1} \times t_{1}}{I_{2} \times t_{2}}$

$\frac{m}{W_{2}}=\frac{4 \times 2 \times 60}{6 \times 40}=2$

$W_{2}=\frac{m}{2}g$