Question

In the previous question, let $V_{0}$ be the volume of each container. All other details remain he same. The number of moles of gas in the container at temperature $2 T_{0}$ will be:

• A. $\frac{p_{0} V_{0}}{2 R T_{0}}$
• B. $\frac{p_{0} V_{0}}{R T_{0}}$
• C. $\frac{2 p_{0} V_{0}}{3 R T_{0}}$
• D. $\frac{p_{0} V_{0}}{3 R T_{0}}$

Answer 1

Answer: (C)

By gas law $n_{2}=\frac{p_{f} v_{0}}{R\left(2 T_{0}\right)}$
$=\frac{4 p_{0} v_{0}}{3 R\left(2 T_{0}\right)}=\frac{2 p_{0} v_{0}}{3 R T_{0}}$