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Chemistry
In the preparation of compounds of Xe, Bartlett had taken O+2 PtF6- as a base compound. This is because
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Q. In the preparation of compounds of $Xe$, Bartlett had taken $O^+_2\, PtF_6^-$ as a base compound. This is because
The p-Block Elements - Part2
A
both $O_2$ and $Xe$ have same size
4%
B
both $O_2$ and $Xe$ have same electron gain enthalpy
12%
C
both $O_2$ and $Xe$ have almost same ionisation enthalpy
73%
D
both $Xe$ and $O_2$ are gases
10%
Solution:
First ionisation enthalpy of $O_2 (1175\, kj\, mol^{-1})$ is almost identical with that of xenon $(1170\, kj \,mol^{-1})$.