1. Tardigrade
  2. Question
  3. Chemistry
  4. In the preparation of CaO from CaCO3 using the equilibrium CaCO3 (s) leftharpoons CaO(s) + CO2(g) Kp is expressed as log Kp = 7.282 - (8500/T) During complete decomposition of CaCO3 , the temperature in celdus to be used is

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Q. In the preparation of $ CaO $ from $ CaCO_3 $ using the equilibrium
$CaCO_3 \,(s) \rightleftharpoons CaO(s) + CO_2(g) $
$ K_p $ is expressed as
$ log \,K_p = 7.282 - \frac{8500}{T} $
During complete decomposition of $ CaCO_3 $ , the temperature in celdus to be used is

AMUAMU 2011Equilibrium

Solution:

For the reaction,
$CaCO_3(s) \rightleftharpoons CaO(s) + CO_2(g)$
$K_p = p_{CO_2}$
$[\because$ Reaction takes place in open atmosphere,
$\therefore p_{CO_2} = 1$]
or $K_p = 1$
$\because log\,K_p = 7.282 - \frac{8500}{T}$
$\therefore log\,1 = 7.282 - \frac{8500}{T}$
(where, $T =$ absolute temperature)
or $ 0 = 7.282 - \frac{8500}{T}$
or $T = 1167.261 \,K$
$= (1167.26 - 273)^{\circ} C$
$ = 894.26^{\circ} C$
$\approx 894^{\circ} C$