Thank you for reporting, we will resolve it shortly
Q.
In the nucleus of ${ }_{11} Na ^{23}$, the number of protons, neutrons and electrons are
AIPMTAIPMT 1991Atoms
Solution:
$Z=11$ i.e., number of protons $=11, A=23$
$\therefore$ Number of neutrons $=A-Z=12$
Number of electron $=0$ (No electron in nucleus)
Therefore $11, 12, 0 .$