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Q.
In the network shown in figure, each resistance is equal to $2 \Omega$. The resistance between the points $A$ and $B$ is
Current Electricity
Solution:
The above circuit is in Wheatstone's bridge balanced condition.
$\therefore $ No current will flow through $R^{\prime}$
$\therefore \frac{1}{ R _{e q}}=\frac{1}{4}+\frac{1}{4}=\frac{2}{4}=\frac{1}{2}$
$R_{e q}=2 \Omega$
