Thank you for reporting, we will resolve it shortly
Q.
In the $L-C$ circuit shown in figure, the current is in direction shown in the figure and charges on the capacitor plates have sign shown in the figure. At this time
Solution:
$\frac{d Q}{d t}=-v e$
$ \Rightarrow Q \downarrow $
$\Rightarrow i \uparrow \rightarrow$ Total energy constant
