1. Tardigrade
  2. Question
  3. Chemistry
  4. In the given reaction: NaOH (.aq.)+HCl (.aq.) arrow NaCl (.aq.)+H2O (.l.) 50 ml of HCl containing 7.3 g of HCl per litre and 100 ml solution of NaOH containing 4 g NaOH per litre reacts, at any instant 0.5 g of NaCl is formed. Hence, the amount of NaOH which did not react is:

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Q. In the given reaction: $NaOH \, \left(\right.aq\left.\right)+HCl \, \left(\right.aq\left.\right) \rightarrow NaCl \, \left(\right.aq\left.\right)+H_{2}O \, \left(\right.l\left.\right)$
50 ml of $HCl$ containing 7.3 g of $HCl$ per litre and 100 ml solution of $NaOH$ containing 4 g $NaOH$ per litre reacts, at any instant 0.5 g of $NaCl$ is formed. Hence, the amount of $NaOH$ which did not react is:

NTA AbhyasNTA Abhyas 2020

Solution:

Milli moles of $NaOH$ in sol $=10$
Milli moles of $HCl$ in sol $=10$
At any instant millimoles of $NaCl$ formed $=\frac{0.5}{58.5}\times 10^{3}\approx8.5$
$\therefore $ Amount of $NaOH$ left $=0.4 \, -\left(\right.0.0085\times 40\left.\right)$
$= \, 0.06 \, g$