Q.
In the given reaction for the preparation of $XeF _{4}$, what is the ratio of $Xe$ and $F _{2}$ used?
$Xe _{(g)}+2 F _{2(g)} \stackrel{873 K , 7 bar }{\longrightarrow } XeF _{4(s)}$
The p-Block Elements - Part2
Solution: