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Q. In the given reaction for the preparation of $XeF _{4}$, what is the ratio of $Xe$ and $F _{2}$ used?
$Xe _{(g)}+2 F _{2(g)} \stackrel{873 K , 7 bar }{\longrightarrow } XeF _{4(s)}$

The p-Block Elements - Part2

Solution:

Xenon tetrafluoride $\left( XeF _{4}\right)$ is prepared by heating a mixture of xenon and fluorine in ratio of $1 : 5$ in a nickel vessel at $873 K$.