Question

In the given reaction:
$CH_{3}-CH_{2}-CH_{2}-O-CH_{2}-CH_{3} \xrightarrow{HCl/\Delta }$
$[X]+[Y]. [X]$ and $[Y]$ will respectively be:

• A. $CH_{3} —CH_{2}—CH_{2}OH$ and $CH_{3}—CH_{2}—Cl$
• B. $CH_{3}—CH_{2}—CH_{2}—Cl$ and $CH_{3}—CH_{2}—OH$
• C. $CH_{3}—CH_{2}—CH_{2}—Cl$ and $CH_{2} = CH_{2}$
• D. $CH_{3}—CH = CH_{2}$ and $CH_{2} = CH_{2}$

Answer 1

Answer: (A)

$CH_{3}-CH_{2}-CH_{2}-O-CH_{2}-CH_{3} \xrightarrow{HCl/\Delta}$
$CH_{3}-CH_{2}-CH_{2}-OH+CH_{3}-CH_{2}-Cl$