Question

In the given reaction

$C_{6}H_{5}-O-CH_{2}-CH_{3}\overset{E x c e s s \, \text{HI} / \Delta \, }{ \rightarrow }\left(X\right)+\left(Y\right)$

X and Y will respectively be

• A. $C_{6}H_{5}I$ and $CH_{3}-CH_{2}-I$
• B. $C_{6}H_{5}-OH$ and $CH_{3}-CH_{2}-I$
• C. $C_{6}H_{5}I$ and $CH_{3}-CH_{2}OH$
• D. $C_{6}H_{5}OH$ and $CH_{2}=CH_{2}$

Answer 1

Answer: (B)

This reaction occurs by $S_{N}2$ mechanism as follows to give phenol and ethyl iodide