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  4. In the given potentiometer circuit arrangement, the balancing length A C is measured to be 250 cm. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes 400 cm. The ratio of the emf of two cells, (ε1/ε2) is :

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Q. In the given potentiometer circuit arrangement, the balancing length $A C$ is measured to be $250 cm$. When the galvanometer connection is shifted from point (1) to point (2) in the given diagram, the balancing length becomes $400 cm$. The ratio of the emf of two cells, $\frac{\varepsilon_{1}}{\varepsilon_{2}}$ is :Physics Question Image

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Solution:

$E_{1}=k l_{1}$ ...(i)
$E_{1}+E_{2}=k l_{2}$ ... (ii)
$\frac{E_{1}}{E_{1}+E_{2}}=\frac{l_{1}}{l_{2}}=\frac{250}{400}=\frac{5}{8}$
$8 E_{1}=5 E_{1}+5 E_{2}$
$3 E_{1}=5 E_{2}$
$\frac{E_{1}}{E_{2}}=\frac{5}{3}$