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Q.
In the given figure, the equivalent capacitance between points $A$ and $B$ is
Electrostatic Potential and Capacitance
Solution:
The equivalent circuit diagrams are as shown in the figure (a) and (b).
The equivalent capacitance between $A$ and $B$ is
$\frac{1}{C_{eq}} = \frac{1}{3C} + \frac{1}{3C}$
$\frac{1}{C_{eq}} = \frac{2}{3C} , C_{eq} = \frac{3}{2} C = 1.5 \,C$
