Question

In the given figure for a projectile

• A. $y=\left[\frac{x_{1} x_{2}}{x_{1}-x_{2}}\right] \tan \theta$
• B. $y=\left[\frac{x_{1} x_{2}}{x_{1}+x_{2}}\right] \tan \theta$
• C. $y=\left[\frac{2 x_{1} x_{2}}{x_{1}+x_{2}}\right] \cos \theta$
• D. $y=\left[\frac{2 x_{1} x_{2}}{x_{1}+x_{2}}\right] \tan \theta$

Answer 1

Answer: (B)

The equation of trajectory for point 'P' can be written as :
$y=x \tan \theta\left(1-\frac{x}{R}\right)=x_{1} \tan \theta\left(1-\frac{x_{1}}{x_{1}+x_{2}}\right)$
$=x_{1} \tan \theta\left(\frac{x_{1}+x_{2}-x_{1}}{x_{1}+x_{2}}\right)$
$y=\frac{x_{1} x_{2}}{x_{1}+x_{2}} \tan \theta$