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Q. In the given figure, charge stored in capacitor in steady state will bePhysics Question Image

Solution:

image
In steady state current drawn from battery
$I=\frac{12}{4+2}=2\, A$
Potential drop across $A B=4 \times 2=8\, V$
This is drop across capacitor also
$q=C V=2 \times 10^{-6} \times 8=16\, \mu C$