Thank you for reporting, we will resolve it shortly
Q.
In the given circuit, with steady current, the potential drop across the capacitor must be
Current Electricity
Solution:
Moving anticlockwise from $A$,
$-i R-V+2 V-2 i R=0$
or $3 i R=V$ or $i=\frac{V}{3 R}$
$V_{A}-V_{B}=i R+V-V=i R$
$\Rightarrow $ Potential drop across $C=\frac{V}{3}$