Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In the given circuit, with steady current, the potential difference across the capacitor must bePhysics Question Image

IIT JEEIIT JEE 2001Electrostatic Potential and Capacitance

Solution:

In steady state condition, no
current will flow through the
capacitor $C$. Current in the outer circuit,
$i= \frac {2V-V}{2R+R}= \frac {V}{3R} $
Potential difference between $A$ and $B$
$V_A-V+V+iR=V_B $
$\therefore V_B-V_A=iR= \left(\frac {V}{3R}\right)R= \frac {V}{3} $
NOTE In this problem charge stored in the capacitor can also be
asked, which is equal to $q=C \frac {V}{3} $ with positive charge on $B$ side and
negative on $A$ side because $V_B >V_A. $

Solution Image