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Q.
In the given circuit, the voltmeter records $5\, V$. The resistance (in $\Omega$ ) of the voltmeter is
Current Electricity
Solution:
Let the resistance of voltmeter be $G \, \Omega$.
$\therefore $ Total resistance of the circuit, $R=\left(\frac{G \times 100}{G+100}+50\right) \, \Omega$
Total current, $i=\frac{V}{R}=\frac{10}{\left(\frac{G \times 100}{G+100}+50\right)}$
Voltage across $100 \, \Omega$ resistance
$=i\left(\frac{G \times 100}{G+100}\right)=\frac{10}{\left(\frac{G \times 100}{G+100}+50\right)} \times\left(\frac{G \times 100}{G+100}\right)$
Reading of voltmeter $=5 \, V$(Given)
$\therefore $ Voltage across $100 \,\Omega=5 \, V$
$\therefore 5=\frac{10}{\left(\frac{G \times 100}{G+100}+50\right)} \times\left(\frac{G \times 100}{G+100}\right)$
$\Rightarrow G=100 \,\Omega$