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Tardigrade
Question
Physics
In the given circuit, the resonant frequency is
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Q. In the given circuit, the resonant frequency is
KCET
KCET 2020
Electromagnetic Induction
A
15.92 Hz
18%
B
159.2 Hz
22%
C
1592 Hz
51%
D
15910 Hz
9%
Solution:
Resonant frequency of an circuit is given by
$f=\frac{1}{2 \pi \sqrt{L C}} $
$=\frac{1}{2 \pi \sqrt{0.5 \times 10^{-3} H \times 20 \times 10^{-6} F}} $
$=1592\, Hz$