Q.
In the given circuit the internal resistance of the $18\, V$ cell is negligible. If $R_1 = 400 \; \Omega , R_3 = 100 \Omega$ and $R_4 = 500 \; \Omega $ and the reading of an ideal voltmeter across $R_4$ is $5V$, then the value $R_2$ will be :
Solution:
$V_{4} = 5V $
$ i_{1} = \frac{V_{4}}{R_{4}} = 0.01 A$
$ V_{3} = i_{1} R_{3} = 1V$
$ V_{3} +V_{4} = 6V = V_{2} $
$ V_{1} + V_{3} + V_{4} = 18 V $
$ V_{1} = 12V $
$ i = \frac{V_{1} }{R_{1}} = 0.03 Amp .$
$ i_{2} = 0.02 Amp V_{2} = 6V $
$ R_{2} = \frac{V_{2} }{i_{2}} = \frac{6}{0.02} = 300 \Omega$
