Thank you for reporting, we will resolve it shortly
Q.
In the given circuit, the current $I_{1}$ is
Current Electricity
Solution:
The circuit can be simplified as follows:
Applying $K C L$ at junction $A$
$I_{3}=I_{1}+I_{2}$ ....... (i)
Applying Kirchhoff's voltage law for the loop $A B C D A$
$-30 I_{1}-40 I_{3}+40=0$
$\Rightarrow -30 I_{1}-40\left(I_{1}+I_{2}\right)+40=0$
$\Rightarrow 7 I_{1}+4 I_{2}=4$ .....(ii)
Applying Kirchhoff's voltage law for the loop $ADEFA$,
$-40 I_{2}-40 I_{3}+80+40=0$
$\Rightarrow -40 I_{2}-40\left(I_{1}+I_{2}\right)=-120$
$\Rightarrow I_{1}+2 I_{2}=3$ ......(iii)
On solving equations (ii) and (iii), $I_{1}=-0.44 A$
