Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. In the given circuit $P$ and $Q$ form the inputs. The output $Y$ is
Question

NTA AbhyasNTA Abhyas 2022

Solution:

From the given circuit, the output $Y$ is
$Y=\overline{(\bar{P}+Q)(P+Q)}$
$Y=\overline{\bar{P} \cdot P+\bar{P} Q+Q \cdot P+Q \cdot Q}$
$Y=\overline{Q+P Q+\bar{P} Q}(\because \bar{P} \cdot P=0)$
$Y=\overline{Q(1+P+\bar{P})}(\because 1+A=1)$
$Y=\bar{Q}$