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Q. In the given circuit, find the current in the wire between points $A$ and $B$ .
Question

NTA AbhyasNTA Abhyas 2022

Solution:

Solution
$i=\frac{32}{\left(\frac{2}{3} + \frac{2}{3}\right) \times \left(10\right)^{3}}=24mA$
$i_{1}=\frac{2}{1 + 2}i=\frac{2}{3}i$
$i_{2}=\frac{i}{3}$
$i_{3}=i_{1}-i_{2}=\frac{i}{3}=\frac{24}{3}=8mA$