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Q. In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance $C$ will be :Physics Question Image

JEE MainJEE Main 2017Alternating Current

Solution:

In steady state, flow of current through capacitor will be zero.
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$i= \frac{E}{r + r_{2}}$
$V_{C} = i r_{2 }C = \frac{Er_{2}C}{r +r_{2}}$
$V_{C } = CE \frac{r_{2}}{r +r_{2}}$