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Q. In the given circuit, a charge of $+80 \mu C$ is given to the upper plate of the $4 \mu F$ capacitor. Then in the steady state, the charge on the upper plate of the $3 \mu F$ capacitor isPhysics Question Image

AIEEEAIEEE 2012

Solution:

Let '$q$' be the final charge on $3 \mu F$ capacitor then
$\frac{80- q }{2}=\frac{ q }{3} \Rightarrow q =48 \mu C$