Question

In the following sequence of the reaction, $ C{{H}_{3}}C{{H}_{2}}Cl\xrightarrow[\Delta ]{Alc.\,\,KCN}A\xrightarrow[in\,ether]{LiAl{{H}_{4}}}B $ the major product B is

• A. $ C{{H}_{3}}C{{H}_{2}}COOH $
• B. $ C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}-OH $
• C. $ C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}} $
• D. $ C{{H}_{3}}C{{H}_{2}}N{{H}_{2}} $

Answer 1

Answer: (C)

$ \underset{Ethyl\,chloride}{\mathop{C{{H}_{3}}C{{H}_{2}}Cl}}\,\xrightarrow[\Delta ]{Alc.\,\,KCN}\underset{Ethyl\,cyanide}{\mathop{C{{H}_{3}}C{{H}_{2}}CN}}\, $ $ \xrightarrow[in\,ether]{LiAl\,{{H}_{4}}}\underset{n-propylamine}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}}}\, $