1. Tardigrade
  2. Question
  3. Chemistry
  4. In the following sequence of reactions the maximum number of atoms present in molecule textC in textsp text3 hybridised state is textA overset textRed texthot textCu texttube arrow textB arrow ( textAlCl) text3( textCH) text3 textCl text(1 texteq text.) textC ( textA is a lowest molecular weight alkyne)

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Q. In the following sequence of reactions the maximum number of atoms present in molecule $\text{C}$ in $\text{sp}^{\text{3}}$ hybridised state is

$\text{A} \overset{\text{Red} \, \text{hot} \, \text{Cu} \, \text{tube}}{ \rightarrow } \text{B} \rightarrow _{\left(\text{AlCl}\right)_{\text{3}}}^{\left(\text{CH}\right)_{\text{3}} \text{Cl} \, \text{(1} \, \text{eq} \text{.)}} \text{C}$

( $\text{A}$ is a lowest molecular weight alkyne)

NTA AbhyasNTA Abhyas 2020Hydrocarbons

Solution:

Here only one C-atom of $C H_{3}$ group is $s p^{3}$ hybridised rest all C- atoms of benzene ring are $s p^{2}$ hybridised.

Solution