1. Tardigrade
  2. Question
  3. Chemistry
  4. In the following sequence of reactions CH3-Br xrightarrowKCN A xrightarrowH3 O+ B xrightarrow [ textether]LiAIH4C , the end product (C) is :

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Q. In the following sequence of reactions $CH_{3}-Br\xrightarrow{KCN} A\xrightarrow{H_{3} O^{+}} B \xrightarrow [\text{ether}]{LiAIH_{4}}C$ , the end product $\left(C\right)$ is :

NTA AbhyasNTA Abhyas 2022

Solution:

When, methyl bromide react with potassium cyanide then form ethyl nitrile via nucleophilic substitution reaction.
Ethyl nitrile on hydrolysis reaction gives ethanoic acid.
Ethanoic acid reduces with lithium aluminium hydride to give ethyl alcohol as the final product.
$CH _3- Br \xrightarrow{ KCN } CH _3- CN (A) \xrightarrow{ H _3 O ^{+}} CH _3- COOH (B) \xrightarrow[\text { ether }]{ LiAlH _4}$ $CH _3- CH _2 OH ( C )$