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Q. In the following redox reaction
$Zn (s)+ NO _3^{-}(a q)+ H ^{+}(a q) \rightarrow Zn ^{2+}(a q)+ NH _4^{+}(a q) Zn (s)$ and $NO _3^{-}(a q)$ respectively are

General Principles and Processes of Isolation of Elements

Solution:

$Zn \rightarrow Zn ^{2+}$
$Zn$ is oxidized hence, it is a reducing agent (reductant)
$\underset{+5}{NO _3^{-}} \rightarrow \underset{-3}{NH _4^{+}}$
$NO _3^{-}$is reduced hence, it is oxidizing agent (oxidant)