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  4. In the following redox reaction, Cu ( OH )2(s)+ N 2 H 4(a q) arrow Cu (s)+ N 2( g ) Number of moles of Cu ( OH )2 reduced by 1 mole of N 2 H 4 is

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Q. In the following redox reaction,
$Cu ( OH )_2(s)+ N _2 H _4(a q) \rightarrow Cu (s)+ N _2( g )$
Number of moles of $Cu ( OH )_2$ reduced by $1$ mole of $N _2 H _4$ is

General Principles and Processes of Isolation of Elements

Solution:

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$\therefore$ Thus, $1$ mole $N _2 H _4 \equiv 2\, mol \,Cu ^{2+}$