Question

In the following reaction; $xA \to yB$
$\log_{10} \left[ - \frac{d[A]}{dt} \right] =\log_{10} \left[ \frac{d[B]}{dt} \right] + 0.3010$
'A' and 'B' respectively can be :

• A. n-Butane and Iso-butane
• B. $2C_2H_4$ and $C_4H_8$
• C. $N_2O_4$ and $NO_2$
• D. $C_2H_2 $ and $C_6H_6$

Answer 1

Answer: (B)

$\log \frac{-d\left[A\right]}{dt} =\log \frac{d\left[B\right]}{dt} +0.3010 $
$ \frac{-d\left[A\right]}{dt} = 2\times\frac{d\left[B\right]}{dt} $
$ \frac{1}{2} \times\frac{-d\left[A\right]}{dt} = \frac{d\left[B\right]}{dt} $
$ 2A \to B$
$ 2C_{2}H_{4} \to C_{4}H_{8} $