1. Tardigrade
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  4. In the following reaction, the energy released is: 41 H1 → 2He4+2e++energy

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Q. In the following reaction, the energy released is: $ {{4}_{1}}\,{{H}^{1}}\,\to {{\,}_{2}}H{{e}^{4}}+2{{e}^{+}}+energy $

EAMCETEAMCET 1997

Solution:

The reaction is given as $ 4{{\,}_{1}}{{H}^{1}}\to {{\,}_{2}}H{{e}^{4}}+2{{\,}_{1}}e{{\,}^{o}}+energy $ $ 4{{\,}_{1}}{{H}^{1}}=4.030372\,\text{amu} $ $ {{\,}_{2}}H{{e}^{4}}=4.002604\,\text{amu} $ $ 2\,{{\,}_{1}}{{e}^{o}}=0.001098\,\text{amu} $ Loss in mass or mass defect $ =4.0303720-(4.002604+0.001098) $ $ =0.02667 $ Energy released $ =0.02667\times 931 $ $ =24.83\,\text{MeV} $