Q.
In the following reaction sequence :
$\underset{{ (C_3H_6Cl_2)}}{I }\xrightarrow{KOH(aq)} II \xrightarrow[(ii) H_2O/H^{+}]{(i)CH_3MgBr} III \xrightarrow{\text{Anhy}.ZnCl_2 + Conc.HCl}$ gives turbidity immediately
The compound $I$ is :
Solution:
Correct answer is (d)

